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Editorial Team
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Asked: 2026-06-15T23:18:08+00:00

Can anybody please explain what is happening below;how does the following bit shift works?

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Can anybody please explain what is happening below;how does the following bit shift works?

Dim pBuffer(11) As Int 
                pBuffer(0)=4 
                'Firmware Version'
                pBuffer(1)=Bit.ShiftRight(Bit.And(firmware_version, 0xFF00),8)
                pBuffer(2)=Bit.And(firmware_version, 0xFF)

Consider firmware_version = 0001

What will be the equivalent java code for this? Can I use Bit.ShiftRight in java? I checked the Java classes and didnt quite understand what will be the equivalent ‘Bit.ShiftRight’ operation in java?

EDIT: Can you explain what exactly is happening here?

pBuffer(1)=Bit.ShiftRight(Bit.And(firmware_version, 0xFF00),8)

How is the AND performed and the bit shift? What is it performed on? Is firmware_version AND 0xFF00 or is it bit shift first? Can you please explain?

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1 Answer

  1. Editorial Team

    VB.NET: Bit.ShiftRight(Bit.And(firmware_version, 0xFF00),8)

    (Bitwise-and of firmware_version and 0xFF00 is shifted right 8 times)

    Java  : (firmware_version & 0xFF00) >> 8 //or >>> for unsigned right-shift

    VB.NET: Bit.And(firmware_version, 0xFF)

    Bitwise And of firmware_version with 0xFF

    Java  : (firmware_version & 0xFF)

    The & operator in Java performs a bitwise AND operation.

    (Reference)

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