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Home/ Questions/Q 8952721
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T13:56:13+00:00 2026-06-15T13:56:13+00:00

Can anybody see why this won’t work. I’m trying to add a simple row

  • 0

Can anybody see why this won’t work. I’m trying to add a simple row to a table and then confirm that it was added correctly. When I try to query the table, my program crashes. My head hurts from staring at this for so long.

addNewGame(1);

Cursor cursor2 = db.query(myDBOpenHelper.GAMES_TABLE, new String [] {"MAX("+GAME_COLUMN+") AS GC"}, null, null, null, null, null);
System.err.println("made it this far");     
String temp = cursor2.getString(cursor.getColumnIndex("GC")); //crash!!!
System.err.println("didn't get here);


private static void addNewGame(int g) {
        ContentValues newValues = new ContentValues();
    SQLiteDatabase db = DBOpenHelper.getWritableDatabase(); 
    newValues.put(GAME_COLUMN, g);
    newValues.put(CIV_COLUMN, "");
    db.insert(myDBOpenHelper.GAMES_TABLE, null, newValues);
}

thread exiting with uncaught exception

Also, here is the code from where the table was created:

private static final String GAMES_CREATE =  "create table " +
            GAMES_TABLE + " (" + KEY_ID +
            " integer primary key autoincrement, " +
            GAME_COLUMN + " text not null, " +
            CIV_COLUMN + " text);";
db.execSQL(GAMES_CREATE);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T13:56:14+00:00Added an answer on June 15, 2026 at 1:56 pm

    Just Nothing Check this.that the cursor will be null?
    just try this code.

    if(cursor2.getcount>0)
    {
    cursor2.moveTofirst();
    String temp = cursor2.getString(cursor.getColumnIndex("GC"));
    }
    

    try this it`s work.

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