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Home/ Questions/Q 401543
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Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T17:02:37+00:00 2026-05-12T17:02:37+00:00

can anybody spot any mistake in this function? .. This is a function which

  • 0

can anybody spot any mistake in this function? .. This is a function which receives a string of type yyyy-mm-dd hh:mm:ss aa and converts to UTC and builds up a string yyyy-mm-dd hh:mm:ss.

function LocalTimetoUTC(localTime)
{

    var time = localTime.split(" "); //Received :- yyyy-mm-dd hh:mm:ss aa
    var yearday = time[0].split("-");
    var dateTime = time[1].split(":");
    var ampm = time[2];
    var hours = 0;

    var year = yearday[0];
    var month = yearday[1]-1; 
    var day = yearday[2];

    hours = dateTime[0];
    var minutes  = dateTime[1];
    var seconds = dateTime[2];

    /* We have to first convert it to 24 hour format
     * 12:00:00 AM : 00:00:00
     * 12:00:00 PM : 12:00:00 
     * Anytime other than 12
     * 1:00:00 AM   : 1:00:00
     * 1:00:00 PM   : 13:00:00
     */
    if(ampm == "PM")
    {       
        //If it is 12PM, adding 12 will create a problem
        if(hours != 12)
        {
            hours +=12;
        }
    }
    else //AM CASE 
    {   
        if(hours == 12)
        {
            hours = 00;
        }
    }


    var now = new Date(year,month,day,hours,minutes,seconds);

    var utcString = now.getUTCFullYear()+"-"
                  +(now.getUTCMonth()+1)+"-"+now.getUTCDate()+""
                   +now.getUTCHours()+":"+now.getUTCMinutes()+":"+now.getUTCSeconds();

    return utcString;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:02:37+00:00Added an answer on May 12, 2026 at 5:02 pm

    Your primary problem is you are using strings in numeric operations. In addition your output formatting has some problems too. Here is an untested refactoring:-

    function convertToUTCString(localTime)
    {
      var dateTimeComponents = localTime.split(" ");
      var dateComponent = dateTimeComponents[0].split("-");
      var timeComponent = dateTimeComponents[1].split(":");
      var ampm = dateTimeComponents[2]
    
      var dat = new Date(parseInt(dateComponent[0]),
        parseInt(dateComponent[1]) -1,
        parseInt(dateComponent[2]),
        parseInt(timeComponent[0]) % 12,
        parseInt(timeComponent[1]),
        parseInt(timeComponent[2]) );
    
      if (ampm == "PM")  // do all locales use 'AM' / 'PM' ??
      {
        dat.setHours(dat.getHours() + 12);
      }
    
      function pad(val)
      {
        var s = val.toString();
        return s.length < 2 ? "0" + s : s
      }
    
      return dat.getUTCFullYear() + "-" +
        pad((dat.getUTCMonth() + 1 )) + "-" + 
        pad(dat.getUTCDate()) + " " + 
        pad(dat.getUTCHours()) + ":" + 
        pad(dat.getUTCMinutes()) + ":" +
        pad(dat.getUTCSeconds());
    }
    
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