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Home/ Questions/Q 6865929
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:06:55+00:00 2026-05-27T03:06:55+00:00

Can anybody tell me why the loop did not stop after the 5 entry?

  • 0

Can anybody tell me why the loop did not stop after the 5 entry?

http://jsbin.com/ucuqot/edit#preview


$(document).ready(function()
{
  someArray = new Array();
  someArray[0] = 't5';
  someArray[1] = 'z12';
  someArray[2] = 'b88';
  someArray[3] = 's55';
  someArray[4] = 'e51';
  someArray[5] = 'o322';
  someArray[6] = 'i22';
  someArray[7] = 'k954';  

  var test =  findXX('o322');   

});

function findXX(word)
{  
  $.each(someArray, function(i)
  {
    $('body').append('-> '+i+'<br />');
    if(someArray[i] == 'someArray')
    {
      return someArray[i]; //<--- did not stop the loop!
    }   
  });  
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:06:55+00:00Added an answer on May 27, 2026 at 3:06 am

    Because when you use a return statement inside an each loop, a “non-false” value will act as a continue, whereas false will act as a break. You will need to return false from the each function. Something like this:

    function findXX(word) {
        var toReturn; 
        $.each(someArray, function(i) {
            $('body').append('-> '+i+'<br />');
            if(someArray[i] == word) {
                toReturn = someArray[i];
                return false;
            }   
        }); 
        return toReturn; 
    }
    

    From the docs:

    We can break the $.each() loop at a particular iteration by making the
    callback function return false. Returning non-false is the same as a
    continue statement in a for loop; it will skip immediately to the next
    iteration.

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