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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:41:55+00:00 2026-05-13T07:41:55+00:00

Can anyone help me with the right syntax to load some div, please I

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Can anyone help me with the right syntax to load some div, please

I try’d to concat it in several ways, except the right way

rcp= "#div02";
$("#content").load("/inc/forms.php " +rcp'"', function(){....

I will keep trying in the meantime

EDIT

AND ACCIDENTLY GOT IT RIGHT (not completely yet)

$(“#content”).load(“/inc/forms.php #” +rcp, function(){…. is ok

BUT before the load function the ajax function is called, and returns with the rcp variable
I think now it is a variable scope problem.
I already try’d setting a global rpc variable, but it’s not working, not yet anyway!

var avp ='';

$("a.order").click(function(e){
e.preventDefault();

$.ajax({
url: "/order/request",
cache: false,
type: "POST",
dataType: "json",
timeout: 5000,
success: function(data)
{
if(data.check){         //ingelogd??


    avp = data.requestpage.avp;
}

}//EINDE success

});//EINDE ajax


$("#content").load("/inc/forms.php #"+avp, function()                                                       
});//EINDE LOAD

});

thanks in adv, Richard

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:41:55+00:00Added an answer on May 13, 2026 at 7:41 am

    You seem to have an extra ” character appending there for some reason which isn’t needed and is probably making it try to find the selector actually called div02″

    rcp= "div02";
    $("#content").load("/inc/forms.php #" +rcp+'"', function(){....
    

    Change that to

        rcp= "div02";
    $("#content").load("/inc/forms.php #" +rcp, function(){....
    

    Edit:

    Your $.ajax() function is returning AFTER your load function – put your load function into the success function of $.ajax

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