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Home/ Questions/Q 3312182
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T21:57:52+00:00 2026-05-17T21:57:52+00:00

Can anyone please explain why the following will compile int a = aAssignments[i]->Count; int

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Can anyone please explain why the following will compile

int a = aAssignments[i]->Count;
int b = fInstanceData->NumRequiredEmpsPerJob[i];
fInstanceData->NumSlotsPerJob[i] = max(a,b);

but

fInstanceData->NumSlotsPerJob[i] = max((int)(aAssignments[i]->Count), (int)(fInstanceData->NumRequiredEmpsPerJob[i])); //why on earth does this not work?

wont? The error it gives is error C2665: 'std::max' : none of the 7 overloads could convert all the argument types

The variable aAssigmments is of type array<List<int>^>^ and fInstanceData->NumRequiredEmpsPerJob is of type array<int>^

The manual for std::max states that it takes values by reference, so it’s clearly doing this implicitly in the first example, so why can’t the compiler do the same for integer values returned by the count property, as in the second example? Can I get a reference to an int explicitly?

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:57:53+00:00Added an answer on May 17, 2026 at 9:57 pm

    (int)(aAssignments[i]->Count) will call the property getter. But it evaluates to a temporary variable (rvalue) which cannot bind to a non-const reference.

    According to my documentation on std::max, the parameters should be const references and everything should work.

    What happens if you explicitly specify the template type parameter, e.g.

    max<int>((int)(aAssignments[i]->Count), (int)(fInstanceData->NumRequiredEmpsPerJob[i]))

    ?

    What about max<int>(a + 0, b + 0) ?

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