Question

Can anyone please tell why this code doesn’t work:

$ser = array('one','two','three','four');
$x = serialize($ser);
$x = unserialize($x);
$x = array_push($x, 'five');
$x = serialize($x);
echo $x;

I think it doesn’t require any further explanation…

The result is only:

i:5;

Answer 1

Dont assign the result of array_push to $x.

array_push($x, 'five'); 

This function returns the new number of elements, which you don’t want to replace your array.

$ser = array('one','two','three','four'); 
$x = serialize($ser); 
$x = unserialize($x); 
array_push($x, 'five'); 
$x = serialize($x); 
var_dump($x);