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Editorial Team
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Asked: 2026-05-13T09:33:33+00:00

can anyone start me off with regard to converting some XML to HTML. I’ve

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can anyone start me off with regard to converting some XML to HTML. I’ve worked on XSLT conversions before, but never from scratch, and I seem to be missing something.

Starting with XML that’s something like this:

<order name="fred" value="123.45">
  <lines>
    <line description="foo" value="123"/>
    <line description="bar" value="0.45"/>
  </lines>
</order>

…and an XSLT file that looks like this:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
  <xsl:decimal-format name="sterling" decimal-separator="." grouping-separator=","/>
  <xsl:output method="html" indent="yes"/>

  <xsl:template match="/">
    <html>
      <head>
        <xsl:apply-templates select="order"/>
      </head>
      <body>
        <table border="2">
          <xsl:apply-templates  select="order/lines/line"/>
        </table>
      </body>
    </html>
  </xsl:template>

  <xsl:template match="order">
    Name is '<xsl:value-of select="@name"/>' and value is <xsl:value-of select="format-number(@value, '£#,###.00', 'sterling')"/>
  </xsl:template>

  <xsl:template match="order/lines/line">
    <tr>
      <td>
        <xsl:value-of select="@description"/>
      </td>
      <td>
        <xsl:value-of select="@value"/>
      </td>
    </tr>
  </xsl:template>

</xsl:stylesheet>

When I do the conversion using an XslCompiledTransform object from C#, I get the basic html but no content for the the lines. The code I used to the the transform isas follows:

private static String GetHtml(String xml)
{
    String result;

    var doc = new XmlDocument();
    doc.LoadXml(xml);

    var transformer = new XslCompiledTransform(true);
    transformer.Load("foobar.xslt");

    using (var writer = new StringWriter())
    {
        transformer.Transform(doc, null, writer);
        result = writer.ToString();
    }

    return result;
}

Any help greatly appreciated.

Ross

(as an aside, what’s the point of the xsl:decimal-format element if, in using the format-number function, I have to provide the format string ?)

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1 Answer

  1. Editorial Team

    This will never be used, as there is no attribute or element named fred:

    <xsl:template match="fred">

    You need something like:

    <xsl:template match="@name">

    And similarly, the apply-templates section calling this attribute needs to change to:

    <xsl:apply-templates select="@name"/>

    Based on the structure of the XML you posted, you need to change every mention of fred to order in your XSLT.

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