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Asked: 2026-05-11T08:42:02+00:00

Can anyone tell me what this cast has for effect (besides setting happyNumber to

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Can anyone tell me what this cast has for effect (besides setting happyNumber to 1337), if any at all, and if it has no other effect, how come I can write code like this??? Is this a compiler bug, or some ‘hidden away feature’ of C++?

int happyNumber = static_cast<int>(123.456, TRUE, 'WTF' , false , 'IS' , NULL , 'GOING' , 0xff , 'ON???' , 1337);

I was surprised this would compile at all. I found it through a bug where I accidentally set the second parameter to something that was meant to go in a function call of the expression being cast. This resulted in a nasty bug where the object was cast from the second parameter, calling the function with only one argument. It compiled… And didn’t initially boom…

I am using Microsoft Visual C++ 2008.

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1 Answer

  1. Static cast takes one argument, but its argument is an expression, and expressions can include the comma operator. Comma is used in situations where you want to evaluate two or more expressions at once for their side effects, e.g.:

    int i, j; for (i=0, j=0; i < 10; i++,j++) {     // do stuff }

    It’s somewhat useful because without it you could only evaluate one expression each for the initializer, condition, and continue parts of the for loop (or any other place an expression is expected). It doesn’t usually make for the clearest code, though, and the semantics are odd. As you observed, a comma-separated sequence evaluates to the value of its last expression.

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