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Home/ Questions/Q 6582085
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Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T16:14:12+00:00 2026-05-25T16:14:12+00:00

Can anyone tell me why I can’t create a new object in my Interactions

  • 0

Can anyone tell me why I can’t create a new object in my Interactions panel or why this program won’t run even though it was compiled?

   import java.util.Random;
/**
 * This program allows a user to enter their first and last name
 * and generate a random user id and default password.
 * 
 * @author Brian Drake
 * @version 9/14/11
 */

   public class UserID {

      private String firstName;

      private String lastName;

      private String userId;

      private String password;


      public UserID(String first, String last) {
         Random generator = new Random();

         firstName = first;

         lastName = last;

         userId = first.substring(0, 3) + last.substring(0, 3)
            + generator.nextInt(1) + (generator.nextInt(7) + 3)
            + generator.nextInt(10);

         password = Integer.toString(generator.nextInt(10) + generator.nextInt(10)
            + generator.nextInt(10) + generator.nextInt(10)
            + generator.nextInt(10) + generator.nextInt(10));

      } 

      public String getId() {
         return userId;
      }

      public String getPassword() {
         return password;
      }

      public boolean setPassword(String randomPass) {

         if (password.length() < 6 || password.length() > 6) {
            randomPass = password;

            return false;       
         }

         else {
            password = randomPass;
         }
         return true;
      }

      public void generateNewPassword() {

         Random generator = new Random();

         password = Integer.toString(generator.nextInt(10) + generator.nextInt(10)
            + generator.nextInt(10) + generator.nextInt(10)
            + generator.nextInt(10) + generator.nextInt(10));

      }

      public String toString(String first, String last) {
         String output = firstName + " " + lastName + "\n";
         output += userId + "\n";
         output += password;
         return output;
      }

   }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:14:12+00:00Added an answer on May 25, 2026 at 4:14 pm

    In the class definition of UserID, you need to assign parameter values while creating an object (because you didn’t create no argument constructor).

    UserID obj=new UserID("firstName","secondName");
    

    Edit:

    Apart from the UserID class, you have to define another class which contains an entry point – main() method.

    public class TestMain
    {
      public static void main(String []args)
       {
         UserID obj=new UserID("firstName","secondName");
         //Using obj reference variable, you can request to the object for any message.
         System.out.println(obj.getId() + " " + obj.getPassword());
       }
    }
    
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