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Home/ Questions/Q 7712579
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Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T01:40:01+00:00 2026-06-01T01:40:01+00:00

Can anyone tell me why the below gives me an empty string? When I

  • 0

Can anyone tell me why the below gives me an empty string? When I console.log(contentArray) in the $.get() callback function it shows the data but when I try to do it where it is in the code below, the result is empty.

sectionArray = [];
contentArray = [];
$(function () {
    if (index == 1) {
        $('menu:eq(' + (section - 1) + ') li a').each(function () {
            sectionArray.push($(this).attr('href'));
        });

        var len = sectionArray.length;

        for (var i = 0; i < len; i++) {
            href2 = sectionArray[i];

            $.get(href2, function (data) {
                string = data.toString();
                contentArray.push(string);
            });
        }
        content = contentArray.toString();
        console.log(content);
    }
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  1. Editorial Team
    Editorial Team
    2026-06-01T01:40:02+00:00Added an answer on June 1, 2026 at 1:40 am

    because ajax request ends after you call console.log() try this:

    $.get(href2, function(data){
        string = data.toString();
        contentArray.push(string);
        content = contentArray.toString();
        console.log(content);
    });
    

    also do ajax request in loop is not best thing to do. that wont work as you want.

    UPDATE:

    also jQuery has async option set to false and your code should work but will work slow. Synchronous requests may temporarily lock the browser.

    UPDATE 2

    maybe try something like this(maybe not so good idea :D):

    var countRequests = len;
    $.get(href2, function(data){
        string = data.toString();
        contentArray.push(string);
        countRequests = countRequests - 1;
        if (countRequests == 0) {
            content = contentArray.toString();
            console.log(content);
            // or create callback
        }
    });
    
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