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Home/ Questions/Q 4085280
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:33:16+00:00 2026-05-20T18:33:16+00:00

Can anyone tell my why this wouldn’t compile? package main type myint int func

  • 0

Can anyone tell my why this wouldn’t compile?

package main

type myint int
func set(a **myint) {
    i := myint(5)
    *a = &i 
}

func main() {
    var k *int
    set( (**myint)(&k) ) // cannot convert &k (type **int) to type **myint
    print( *k )
}

My reasoning so far is this. All types in Golang are different, but it allows to convert from one type to another with C-like cast syntax as long as underlying types are identical. In my example, converting ‘int’ to ‘myint’ is not a problem. ‘*int’ to ‘*myint’ isn’t either. It’s when you have pointer to pointer problems arise. I’ve been stuck on this for the second day now. Any help is appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:33:16+00:00Added an answer on May 20, 2026 at 6:33 pm

    Here’s my analysis.

    (**myint)(&k) — cannot convert &k (type **int) to type **myint:

    type **int and type **myint are unnamed pointer types and their pointer base types, type *int and type *myint, don’t have identical underlying types.

    If T (*int or *myint) is a pointer type literal, the corresponding underlying type is T itself.

    (*myint)(k) — can convert k (type *int) to type *myint:

    type *int and type *myint are unnamed pointer types and their pointer base types, type int and type myint (type myint int), have identical underlying types.

    If T (int) is a predeclared type, the corresponding underlying type is T itself. If T (myint) is neither a predeclared type or nor a type literal, T’s underlying type is the underlying type of the type to which T refers in its type declaration (type myint int).

    (myint)(*k) — can convert *k (type int) to type myint:

    type int and type myint have identical underlying types.

    If T (int) is a predeclared type, the corresponding underlying type is T itself. If T (myint) is neither a predeclared type or nor a type literal, T’s underlying type is the underlying type of the type to which T refers in its type declaration (type myint int).

    Here’s the underlying type example from the Types section revised to use integers and int pointers.

    type T1 int
    type T2 T1
    type T3 *T1
    type T4 T3
    

    The underlying type of int, T1, and T2 is int. The underlying type of *T1, T3, and T4 is *T1.

    References:

    The Go Programming Language Specification

    Conversions

    Types

    Properties of types and values

    Type declarations

    Predeclared identifiers

    Pointer Type

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