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Home/ Questions/Q 7737171
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T07:55:45+00:00 2026-06-01T07:55:45+00:00

Can I do the following in PHP? $lstrClassName = ‘Class’; $lstrMethodName = ‘function’; $laParameters

  • 0

Can I do the following in PHP?

$lstrClassName  = 'Class';
$lstrMethodName = 'function';
$laParameters   = array('foo' => 1, 'bar' => 2);

$this->$lstrClassName->$lstrMethodName($laParameters);

The solution I’m using now, is by calling the function with eval() like so:

eval('$this->'.$lstrClassName.'->'.$lstrMethodName.'($laParameters);');

I’m curious if there is a beter way to solve this.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T07:55:46+00:00Added an answer on June 1, 2026 at 7:55 am

    You don’t need eval to do that … depending on your version

    Examples

    class Test {
        function hello() {
            echo "Hello ";
        }
    
        function world() {
            return new Foo ();
        }
    }
    
    class Foo {
    
        function world() {
            echo " world" ;
            return new Bar() ;
        }
    
        function baba() {
    
        }
    }
    
    class Bar {
    
        function world($name) {
            echo $name;
        }
    
    
    }
    
    
    $class = "Test";
    $hello = "hello";
    $world = "world";
    $object = new $class ();
    $object->$hello ();
    $object->$world ()->$world ();
    $object->$world ()->$world ()->$world(" baba ");
    

    Output

    Hello World baba
    

    And if you are using PHP 5.4 you can just call it directly without having to declare variables

    You might also want to look at call_user_func http://php.net/manual/en/function.call-user-func.php

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