Question

Can I print a pointer in an OpenCL function?
I can use printf in kernel functions however I can’t find the way to print a pointer.

Is there some equivalent to the following?:

int *ptr = 5;
printf("%p \n", (void *)ptr);

Answer 1

What is wrong with this?

int x = 5;
int *ptr;
ptr = &x;
printf("%p \n", ptr);

You can’t make ptr point to 5. Pointers must point to memory on:

The stack: int x
or
the heap: int* ptr = new int(5)