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Home/ Questions/Q 8468373
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T15:54:46+00:00 2026-06-10T15:54:46+00:00

Can I use deserialize to generate objects from xmls which are not generated by

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Can I use deserialize to generate objects from xmls which are not generated by serialization?

Say, if I have a xml file like this

<Person>
  <Cop name ="n1" />
  <Cop name ="n2" />
</Person>

Can I deserialize it as an Object person with an IEnumberable? or do i need to serialize Object Person with an IEnumerable property then the deserialization?

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  1. Editorial Team
    Editorial Team
    2026-06-10T15:54:47+00:00Added an answer on June 10, 2026 at 3:54 pm

    Of course you can deserialize XML that has not been generated by serialization, you just have to make sure you generate or write the correct class structure with fitting attributes to match the XML structure. And I am not sure an IEnumerable is possible but it is possible to use an List<T> or T[]. The following is a sample with a List<T>:

                string xml = @"<Person>
      <Cop name =""n1"" />
      <Cop name =""n2"" />
    </Person>";
    
    
                XmlSerializer ser = new XmlSerializer(typeof(Person));
    
                Person p1 = (Person)ser.Deserialize(new StringReader(xml));
    
                foreach (Cop cop in p1.Cops)
                {
                    Console.WriteLine(cop.Name);
                }
            }
        }
    
    
    
        public class Person
        {
            [XmlElement(ElementName="Cop")]
            public List<Cop> Cops { get; set; }
        }
    
        public class Cop
        {
            [XmlAttribute(AttributeName="name")]
            public string Name { get; set; }
        }
    

    That outputs

    n1
    n2
    
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