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Home/ Questions/Q 8784651
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Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T21:09:04+00:00 2026-06-13T21:09:04+00:00

can not reproduce deadlock using the next code I am trying yo get a

  • 0

can not reproduce deadlock using the next code

I am trying yo get a deadlock using the next code,
but it seems that it works good.

Please see below:

public class Deadlock {

    static Object lock1 = new Object();
    static Object lock2 = new Object();

    public static void main(String[] args) {

        new Thread(new Runnable() {
            @Override
            public void run() {
                while (true) {
                    synchronized (lock1) {
                        System.out.println("Thread 1: locked lock1");
                    }
                    try {
                        Thread.sleep(100);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    synchronized (lock2) {
                        System.out.println("Thread 1: locked lock2");
                    }
                }
            }
        }).start();

        new Thread(new Runnable() {
            @Override
            public void run() {
                while (true) {
                    synchronized (lock2) {
                        System.out.println("Thread 2: locked lock2");
                    }
                    try {
                        Thread.sleep(50);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    synchronized (lock1) {
                        System.out.println("Thread 2: locked lock1");
                    }
                }
            }
        }).start();

    }

}

What I don’t understand in this case or what’s wrong in this code?

  • 1 1 Answer
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T21:09:06+00:00Added an answer on June 13, 2026 at 9:09 pm

    Why would the above code cause a deadlock? Each thread only locks one lock at a time, so if the other thread tries to lock it, it just has to wait for the first one to release it.

    You would have a serious risk of deadlock if the threads did

    synchronized (lock1) {
        synchronized (lock2) {
            ...
        }
    }
    

    and

    synchronized (lock2) {
        synchronized (lock1) {
            ...
        }
    }
    
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