Question

Can some one explain to me the out put of this simple code segment?

int i=7;
int j=3*i-- + 2;
printf("%d %d",i,j)

When I compile I get 6,23.

How does it come to 23? I thought it would be 3*7=21 decrease to 20 and added 2 is 22 not 23?

Answer 1

int i = 7; /* i is 7 */
int j = (3 * (i--)) /* means 3 * 7 */ + 2; /* 3 * 7 + 2 = 23 */
/* i is now 6, because it was decreased by the postfix -- operator */
printf("%d %d", i /* 6 */, j /* 23 */);