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Home/ Questions/Q 7935449
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:55:31+00:00 2026-06-03T21:55:31+00:00

Can somebody explain me what is being done in the CVector CVector::operator+ (CVector param).

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Can somebody explain me what is being done in the CVector CVector::operator+ (CVector param). How does the dot operator work with temp. I understand when you do object.function() but how does it make sense to do object.object does this just set them both equal to each other? Confused!!

#include <iostream>
using namespace std;

class CVector {
  public:
int x,y;
CVector () {};
CVector (int,int);
CVector operator + (CVector);
};

CVector::CVector (int a, int b) {
  x = a;
  y = b;
}

CVector CVector::operator+ (CVector param) {
   CVector temp;
   temp.x = x + param.x;
   temp.y = y + param.y;
   return (temp);
 }

 int main () {
   CVector a (3,1);
   CVector b (1,2);
   CVector c;
   c = a + b;
   cout << c.x << "," << c.y;
   return 0;
 }
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  1. Editorial Team
    Editorial Team
    2026-06-03T21:55:33+00:00Added an answer on June 3, 2026 at 9:55 pm

    This is called operator overloading. What it is doing in this case is allowing you to add two of CVector objects together, as shown in the main function.

    When a + b occurs in the main function, the operator+ method of the a object is called, with b as the param. It thus constructs a temp object that combines the coordinates of the two, and returns it.

    ETA: Rereading your question, I think you might also be asking what the line

    temp.x = x + param.x;
    

    means. Note that C++ objects don’t just have functions they can call (like object.function()), they have members, which are themselves variables that can be accessed and changed. In this case, x and y are ints that belong to the CVector class. Read this tutorial closely.

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