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Home/ Questions/Q 762695
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T16:26:05+00:00 2026-05-14T16:26:05+00:00

Can somebody explain the following code please? #if 1 // loop type #define FOR_IS_FASTER

  • 0

Can somebody explain the following code please?

#if 1

// loop type
#define FOR_IS_FASTER 1
#define WHILE_IS_FASTER 0
// indexing type
#define PREINCREMENT_IS_FASTER 1
#define POSTINCREMENT_IS_FASTER 0

#else

// loop type
#define FOR_IS_FASTER 1
#define WHILE_IS_FASTER 0
// indexing type
#define PREINCREMENT_IS_FASTER 0
#define POSTINCREMENT_IS_FASTER 1

#endif


#if PREINCREMENT_IS_FASTER
#define ZXP(z) (*++(z))
#define ZX(z) (*(z))
#define PZ(z) (++(z))
#define ZP(z) (z)
#define ZOFF (1)
#elif POSTINCREMENT_IS_FASTER
#define ZXP(z) (*(z)++)
#define ZX(z) (*(z))
#define PZ(z) (z)
#define ZP(z) ((z)++)
#define ZOFF (0)
#endif

I can understand what the functions are doing but for example
how does the pre-processor choose which ZXP will be execute if we call it later?
What do the 1 and 0 stand for?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T16:26:06+00:00Added an answer on May 14, 2026 at 4:26 pm

    The #if 1 triggers the first group of #defines, which set PREINCREMENT_IS_FASTER to 1. Because of this, #if PREINCREMENT_IS_FASTER triggers the first #define ZXP....

    There is nothing exceptional about 1 and 0 in this context. The #if preprocessor directive succeeds if its argument is non-zero.

    You can switch to the alternate form by changing the #if 1 at the top of the file with #if 0. (Thank you @rabidmachine for the tip.)

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