Question

Can somebody please help me with the if statement and arrays. So for example I type in 0001 in the array "1" is [3]. I’m trying to get it to print "working" if 1 is typed on array [3].

This code should explain it more:

original = raw_input("Type is your input? ")
original_as_array = list(original)
print original_as_array
print original[3]

if (original[3] == 1):
    print "working"

Answer 1

This is because you are comparing an int with a single character (type str). Change your if-statement to:

if (original[3] == "1"):
    print "working"

and it will work.

Your input from the key consists of characters ('0001'), so your comparison has to take that into account.

E.g.,

type(original[3])
str

type(1)
int