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Home/ Questions/Q 8867755
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T17:07:02+00:00 2026-06-14T17:07:02+00:00

Can someone explain this function? var bindbind = Function.prototype.bind.bind(Function.prototype.bind); I understand the result it

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Can someone explain this function?

var bindbind = Function.prototype.bind.bind(Function.prototype.bind);

I understand the result it produce:

var bindedContextFunc = bindbind(function)(context);
bindedContextFunc(args);

But do not understand process of creating this functions, I mean part bind(Function.prototype.bind)

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  1. Editorial Team
    Editorial Team
    2026-06-14T17:07:03+00:00Added an answer on June 14, 2026 at 5:07 pm

    OK. We have three times the Function.prototype.bind function here, whose (simplified) code

    function bind(context) {
        var fn = this;
        return function() {
            return fn.apply(context, arguments);
        }
    }
    

    I will abbreviate in a more functional style with lots of partial application: bindfn(context) -> fncontext.

    So what does it do? You have got bind.call(bind, bind) or bindbind(bind). Let’s expand this to bindbind. What if we now supplied some arguments to it?

    bindbind(bind) (fn) (context)

    bindbind(fn) (context)

    bindfn(context)

    fncontext

    Here we are. We can assign this to some variables to make the result clearer:

    bindbind = bindbind(bind)

    bindfn = bindbindanything(fn) // bindfn

    contextbindfn = bindfnanything(context) // fncontext

    result = contextbindfnanything(args) // fncontext(args)

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