Question

Can someone explain to me how to use multiple models with a single view in which each of the models represent a DB table?

What I’ve currently done is created a model file for each model.

Example Model:

[Table("Order")]
public class OrderModel
{
    [Key, Column(Order = 0)]
    [DatabaseGeneratedAttribute(DatabaseGeneratedOption.Identity)]
    public int OrderID { get; set; }

    [Key, Column(Order = 1)]
    public int UserID { get; set; }
    public UserProfile Account { get; set; }

    public DateTime Date { get; set; }
    public int ShipLocation { get; set; }
    public string PONumber { get; set; }

    public int StatusID { get; set; }
    public StatusModel Status { get; set; }
}

Here is the other model that encompases all the models to use in a single controller / view.

public class OrderPlacementModel
{
    public OrderModel OrderChild { get; set; }
    public OrderItemsModel OrderItemsChild { get; set; }
    public StatusModel StatusChild { get; set; }
    public MaterialsModel MaterialsChild { get; set; }
    public CategoryModel CategoryChild { get; set; }
    public PackModel PackChild { get; set; }
}

Answer 1

public ActionResult PlaceOrder()
{
  var viewModel = new OrderPlacementModel
  {
    OrderChild = new OrderModel(),//or fetch this object from your data source
    OrderItemsChild = new OrderItemsChild(),
    //...etcetera
  };
  return View(viewModel);
}

Edit

Or, if you’ve strongly typed your view to a List<OrderPlacementModel> instead of a single instance, you could do something similar to this:

public ActionResult PlaceOrder()
    {
      var viewModel = new List<OrderPlacementModel>();
      var model = new OrderPlacementModel
      {
        OrderChild = new OrderModel(),//or fetch this object from your data source
        OrderItemsChild = new OrderItemsChild(),
        //...etcetera
      };
      viewModel.Add(model);
      //lather, rinse, repeat for however many instances you need to send to your view.
      return View(viewModel);
    }