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Home/ Questions/Q 7853201
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T19:36:46+00:00 2026-06-02T19:36:46+00:00

Can someone give me an example/explanation what this regular expression does: (?![#$]) This is

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Can someone give me an example/explanation what this regular expression does:

(?![#$])

This is part of <%(?![#$])(([^%]*)%)*?> which is what ASP.NET uses to parse server-side code blocks. I understand the second part of the expression but not the first.

I checked the documentation and found (?! ...) means a zero-width negative lookahead but I’m not entirely sure I understand what that means. Any input I tried so far that looks like <% ... %> seems to work – I wonder why this first sub-expression is even there.

Edit:
I came up with this expression for picking up ASP.NET expressions: <%.+?%> then I found the one Microsoft made (the above full expression in question). I’m trying to understand why they chose that particular expression when mine seems a lot simpler. (I’m trying to see if my expression ignores certain boundary conditions that the MS one doesn’t.)

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  1. Editorial Team
    Editorial Team
    2026-06-02T19:36:49+00:00Added an answer on June 2, 2026 at 7:36 pm

    It’s a negative lookahead assertion that matches if the next character is not # or $, but doesn’t consume it.

    It’s very simlar to the negative character class [^#$] except that the negative character class also consumes the character, preventing it from being matched by the rest of the expression.

    To see the difference consider matching <%test%>.

    • The expression <%(?![#$])(([^%]*)%)*?> captures test%. (rubular)
    • The expression <%[^#$](([^%]*)%)*?> captures est% because the t was consumed by the negative character class. (rubular)
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