Can someone please point out what I am doing wrong in the following code?
int* a = NULL;
int* b = NULL;
a = new int[map->mapSize.width];
b = new int[map->mapSize.height];
layer->tileGids = new int[a][b];
Here’s what the code uses:
typedef struct _size {
int width, height;
} size;
class Map {
size mapSize;
}
class Layer {
int * tileGids;
}
EDIT: Compiler-Errors (in line 6 of the first bit of code):
- error: expression in new-declarator must have integral or enumeration type|
- error: ‘b’ cannot appear in a constant-expression|
Solution:
I have decided to accept lightalchemist’s answer. In essence, what works for me is use a vector instead of the array. Vector manages the memory for you and hence is a lot easier to deal with.
Firstly, your variables “a” and “b” are pointers. Your code:
layer->tileGids = new int[a][b]
is the root cause of the problem.
I’m trying to guess your intention here and I think what you are trying to do is make layer.tileGids a 2 dimension array to reference a “grid” of size (mapSize.Width, mapSize.height) so that you can refer to each “cell” in the grid using layer.tileGids[x][y].
If you are indeed trying to create a 2 dimension array, there are 2 methods to do it.
Method 1:
To initialize it:
Now you can access the items in layer.tileGids using:
To deallocate this data structure, similar to how you allocate it, you need to deallocate each dynamically allocated array in each “row”:
Method 2:
Now another easier, less messy method (avoid pointers) is to use the C++ vector class. You need to make the following changes:
To initialize:
To access the elements:
Note that for the second method using vectors, you do not have to do any memory cleanup as is required in the first method because the vector will automatically take care of it. However, because a vector can grow dynamically i.e. you can add items to it, you lose the safety of having a fixed size array i.e. someone could accidentally increase the size of your grid if you use the vector method but if he tries to do that when you intialized it using the first method above an error will occur and you will immediately know that something is wrong.