Question

Can someone please tell me what is the issue with this code.
Basically what I am trying to do is to identify the renter based on their IDs rather than names (in case there are more renters with the same name). Thank you

SELECT DISTINCT P.PROPERTYId, P.PROPERTYName, T.TYPEName 
FROM RENTAL R, PROPERTY P, TYPE T
Group by P.PROPERTYId, P.PROPERTYName, T.TYPEName 
HAVING RENTERId = (SELECT RENTERId FROM RENTER
WHERE RENTERFirstName = 'AL'
AND RENTERLastName = 'SMITH')
AND R.PROPERTYId = P.PROPERTYId
AND P.TYPEId = T.TYPEId
AND T.TYPEName = 'VILLA';

Answer 1

Try this instead.

SELECT DISTINCT 
     Renter.RenterID, 
     Property.PropertyId, 
     Property.PropertyName, 
     Type.TYPEName  
FROM Rental
    inner join Property on Rental.PropertyID = Property.PropertyID
    inner join Type on Property.TypeID = Type.TypeID
    inner join Renter on Rental.RenterID = Renter.RenterID
where Type.TypeName = 'villa'
and Renter.RenterFirstName = 'al'
and Renter.RenterLastName = 'smith'

Note how the tables are linked using the join syntax, and the where clause is reserved for filtering.