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Home/ Questions/Q 6981167
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T18:07:16+00:00 2026-05-27T18:07:16+00:00

Can someone please tell me why this code will not work? It does compile.

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Can someone please tell me why this code will not work? It does compile. When I type decrypt as the argv[1] argument in the command line, it still gives me the else output. i.e. argv[1] is not satisfied even though it should be. This is a work in progress so ignore the other code

 if ((argv[1] == "decrypt"))
      { 
      printf("Decrypting...\n");
        c = getc(fp1);
        if (c != EOF)
          { 
          fread(inputbuffer, sizeof(char), 50 , fp1);   
            printf("%s", inputbuffer);
            /*while(inputbuffer[i]!=EOF)
            {
            fputc((inputbuffer[i] / 2) - 5, fp2);
            }*/
          } 
      }

      else {printf("argv not working");}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:07:17+00:00Added an answer on May 27, 2026 at 6:07 pm

    You need to use strcmp() to compare strings:

    if ((strcmp(argv[1], "decrypt") == 0)
    

    More detail:

    What you are comparing are the two memory addresses for the different strings, which are stored in different locations. Doing so essentially looks like this:

    if(0x00403064 == 0x002D316A) // Two memory locations
    {
        printf("Yes, equal");
    }
    
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