Question

Can someone remind me why this works?

A function requiring int* could take as input an (obviously)

int *integer;

but it could also accept

&var->integer

with var being var_t*, where var_t:

typedef struct {
    int integer;
} var_t;

why is the 2nd accepted?

edit: oopsy, question is same but var is actually a var_t* (and not a var_t) to be more precise.

Answer 1

Let’s break it down.

var is a var_t*.

var->integer is an int.

&var->integer is an int*.