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Home/ Questions/Q 7164107
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T14:00:55+00:00 2026-05-28T14:00:55+00:00

Can someone see what I’m doing wrong with this php array? Im trying to

  • 0

Can someone see what I’m doing wrong with this php array? I”m trying to create a dynamic array but somehow it not working and get an Server internal error when attempting to access it from a browser

$index = 0;
$columnIndex = 0

while($row = mysqli_fetch_array($result, MYSQL_NUM))
{
  $test = array();
  $test[$arrayIndex] = $row[$columnIndex];
  $coumnIndex = 1;

  if(is_string($row[$number]))
  { 
    preg_match("/(?:\d+\.)?(?:\s*)?$stop?(?:\s*)?(.*):(.*)",{$row[$columnIndex]},$match1);     
    $test[$index] = '<p> <strong> . $match1[1] . </strong> . $match1[2] . </p>';
  }      

  ++$arrayIndex; 
  ++$columnIndex;   
}

$jsonData = json_encode($test);
echo $jsonData;
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  1. Editorial Team
    Editorial Team
    2026-05-28T14:00:56+00:00Added an answer on May 28, 2026 at 2:00 pm

    You’re getting the error most likely because you’re doing $test[$arrayIndex] = $row[$columnIndex]; when I don’t see $arrayIndex defined (thus it’s null). You can’t set a null array index.

    If you want a simple dynamic array in PHP, you could do something like this instead:

    $test = array();
    while(/* however you want to define your loop */) {
        $test[] = /* something */;
    }
    

    And you’ll wind up with an array $test that contains whatever you put in /* something */ on each line. Look at the section entitled “Creating/modifying with square bracket syntax” on the PHP Arrays page.

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