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Home/ Questions/Q 8330235
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T02:03:52+00:00 2026-06-09T02:03:52+00:00

Can someone tell me how to remove all the child elements and place them

  • 0

Can someone tell me how to remove all the child elements and place them in a comma-separated line in the parent node, also removing thumbURl and title element of images completely I already have to do a transformation of this file and this is the xs:

<?xml version="1.0" encoding="UTF-8"?>
 <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:template match="@* | node()">
     <xsl:copy>
       <xsl:apply-templates select="@* | node()" />
   </xsl:copy>
   </xsl:template>
   <xsl:template match="propertyURL/text()">
     <xsl:call-template name="string-replace-all">
       <xsl:with-param name="text"    select="."/>
       <xsl:with-param name="replace" select="'?ref=0'"/>
       <xsl:with-param name="by"      select="'?ref=1000'"/>
     </xsl:call-template>
   </xsl:template>
   <xsl:template name="string-replace-all">
     <xsl:param name="text"/>
     <xsl:param name="replace"/>
     <xsl:param name="by"/>
     <xsl:choose>
       <xsl:when test="contains($text, $replace)">
         <xsl:value-of select="substring-before($text,$replace)"/>
         <xsl:value-of select="$by"/>
         <xsl:call-template name="string-replace-all">
           <xsl:with-param name="text" select="substring-after($text,$replace)"/>
           <xsl:with-param name="replace" select="$replace"/>
           <xsl:with-param name="by" select="$by"/>
         </xsl:call-template>
       </xsl:when>
        <xsl:otherwise>
         <xsl:value-of select="$text"/>
        </xsl:otherwise>
    </xsl:choose>
  </xsl:template>
</xsl:stylesheet>

this is what the data i need to modifiy looks like

 <p id="1">
  <amenities>
   <amenity>Air conditioning</amenity>
   <amenity>Lift/elevator</amenity> 
   <amenity>Pets accepted</amenity>
   <amenity>Guarded car park</amenity>
   <amenity>Private parking</amenity>
   <amenity>Garage</amenity>
   <amenity>Limousine service</amenity>
  </amenities>
  <images> 
   <image num="1">
    <imageURL>path/to/image.url1</imageURL>
    <thumbURL>..</thumbURL>  
    <title>..</title>
   </image>
   <image num="2">
    <imageURL>path/to/image.url2</imageURL>
    <thumbURL>..</thumbURL>
     <title>..</title>
    </image>
   </images>
  </p>

this is what i need to do with the data:

<p>
 <amenities>
   Air conditioning,Lift/elevator,Pets accepted,Guarded car park,....
 </amenities>
 <images>
  <imageURL>path/to/image.url1</imageURL>
  <imageURL>path/to/image.url2</imageURL>
 </images>
</p>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T02:03:55+00:00Added an answer on June 9, 2026 at 2:03 am

    How about something like this…

    XSLT 1.0

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:output indent="yes"/>
        <xsl:strip-space elements="*"/>
    
        <xsl:template match="node()">
            <xsl:copy>
                <xsl:apply-templates select="node()"/>
            </xsl:copy>
        </xsl:template>
    
        <xsl:template match="amenity">
            <xsl:value-of select="."/>
            <xsl:if test="following-sibling::amenity">,</xsl:if>
        </xsl:template>
    
        <xsl:template match="image">
            <xsl:apply-templates select="imageURL"/>
        </xsl:template>
    
    </xsl:stylesheet>
    

    Output

    <p>
       <amenities>Air conditioning,Lift/elevator,Pets accepted,Guarded car park,Private parking,Garage,Limousine service</amenities>
       <images>
          <imageURL>path/to/image.url1</imageURL>
          <imageURL>path/to/image.url2</imageURL>
       </images>
    </p>
    
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