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Home/ Questions/Q 6650199
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:51:52+00:00 2026-05-26T00:51:52+00:00

Can someone tell me the difference between these two versions of a declaration of

  • 0

Can someone tell me the difference between these two versions of a declaration of a structure?

struct S
{
  uint8_t a;
};

and

const struct S
{
  uint8_t a;
}

Followed by:

void main(void)
{
  struct S s = {1};
  s.a++;
}

Hint, i’ve tried both versions for S in Visual Studio C++ 2010 Express so I know that both compile with errors.

Is the “const struct” doing nothing at all? “const struct S s = {1};” certainly does, but that’s not the issue at the moment.

Regards
Rich

/********************************************/

I’ve just worked out what

const struct <typename> <{type}> <variable instances a, b, .., z>;

is doing:

When const is present before the “struct”, all variable instances are const, as though they’d be defined with:

const struct <typename> a, b, z;

So it does do something, but not when there’s no instance definitions in-line with the struct declaration.

Rich

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:51:53+00:00Added an answer on May 26, 2026 at 12:51 am

    With:

    const struct S
    {
      uint8_t a;
    };
    

    The const qualifier there is nonsense, and may even cause a compilation error with some C compilers. gcc issues a warning.

    The intent appears to be to declare the data type struct S. In this case, the proper syntax is:

    struct S
    {
      uint8_t a;
    };
    
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