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Home/ Questions/Q 3396520
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:25:04+00:00 2026-05-18T04:25:04+00:00

Can someone tell me why this won’t work? var top = 0; for (divToPosition

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Can someone tell me why this won’t work?

var top = 0;
for (divToPosition in $('.positionableDiv')) {
   divToPosition.css('top',top+'px');
   top = top + 30;
}
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  1. Editorial Team
    Editorial Team
    2026-05-18T04:25:05+00:00Added an answer on May 18, 2026 at 4:25 am

    The first reason would be the misuse of the for loop.

    jQuery has an idiom for looping over selected elements..

    var top = 0;
    $('.positionableDiv').each(function() {
       $(this).css('top',top+'px');
       top = top + 30;
    });
    

    Please take a look at for…in for a better understanding of the way a for…in loop works in javascript, it does not enumerate in the same way as say .NET or Java.

    From Article:

    Although it may be tempting to use this as a way to iterate over an Array, this is a bad idea.

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