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Home/ Questions/Q 3347752
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:27:34+00:00 2026-05-18T01:27:34+00:00

Can this Python code be shortened and still be readable using itertools and sets?

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Can this Python code be shortened and still be readable using itertools and sets?

result = {}
for widget_type, app in widgets:
    if widget_type not in result:
        result[widget_type] = []
    result[widget_type].append(app)

I can think of this only:

widget_types = zip(*widgets)[0]
dict([k, [v for w, v in widgets if w == k]) for k in set(widget_types)])
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  1. Editorial Team
    Editorial Team
    2026-05-18T01:27:34+00:00Added an answer on May 18, 2026 at 1:27 am

    You can use a defaultdict(list).

    from collections import defaultdict
    
    result = defaultdict(list)
    for widget_type, app in widgets:
        result[widget_type].append(app)
    
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