Question

Can you please take a look at following code and let me know why I am not able to run the program?

enter code here
 $(document).ready(function()
  {
  var comp=new Array("AAPL","MSFT","XRTX&");
  var t = setInterval(function(){getPrice();},200);});
  function getPrice() {
    for (var i=0;i<comp.length;i++){
    $.getJSON('https://finance.google.com/finance/info?client=ig&q='+comp[i]+'&callback=?', function(response){
  var stockInfo = response[0];
  var stockString = '<div id="stockprice">';
   stockString += 'Candente Copper: DNT $'+''+stockInfo.l+'';
   stockString += '</div>';
   $('#stockprice').replaceWith(stockString);
   $("#stockprice:contains('-')").addClass('red'); 
   $("#stockprice:contains('+')").addClass('green');
   }      
   });
   }​

Is there any problem with my Array object or other parts of program has issue? Please be advised that the code works fine without calling the array elements.

Thanks

Answer 1

Your {s, }s, (s and )s do not all match up correctly. Also, in order for your function to have a reference to the comp variable, they must both be in the same function scope, in this case: $(document).ready(function(){ ... });. You’ll notice that I also increased your setInterval to 2000 (2s).

EXAMPLE

$(document).ready(function()
{
   var comp = new Array("AAPL","MSFT","XRTX&");
   var t = setInterval(function(){getPrice();},2000);

    function getPrice() 
    {
       for (var i=0;i<comp.length;i++){
        $.getJSON('https://finance.google.com/finance/info?client=ig&q='+comp[i]+'&callback=?', function(response){
         var stockInfo = response[0];
         var stockString = '<div id="stockprice">';
         stockString += 'Candente Copper: DNT $'+''+stockInfo.l+'';
         stockString += '</div>';

         $('#stockprice').replaceWith(stockString);
         $("#stockprice:contains('-')").addClass('red');  
         $("#stockprice:contains('+')").addClass('green');
       });
      }
    }
});​