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Home/ Questions/Q 6106617
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T14:05:56+00:00 2026-05-23T14:05:56+00:00

//cannot declare operator<<(…) here: //forward declarations: class External; template<class T, class Y> class External::Internal;

  • 0
//cannot declare operator<<(...) here:
//forward declarations:
class External;

template<class T, class Y>
class External::Internal;

template<class T, class Y>
std::ostream& operator<<(std::ostream& out, const External::Internal<T,Y>&);

class External
{
    template<class T, class Y>
    class Internal
    {};

    Internal data_;

    void print() {
        /*out is a std::ostream*/
        out << data_;
    }
};

template<class T, class Y>
std::ostream& operator<<(std::ostream& out, const External::Internal<T,Y>&)
{ }

I do want to implement operator<< for Internal but there is a problem when I try to use this operator call from External: It doesn’t see this operator when this operator is declared under the definition of this class, and there seems to be no way of declaring this operator above this class definition.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T14:05:57+00:00Added an answer on May 23, 2026 at 2:05 pm

    If you’re asking how to define Internal<>::operator<< as a friend, then:

    class External
    {
      template<class T, class Y>
      class Internal
      {
        friend std::ostream& operator <<(std::ostream& out, const Internal&)
        {
          // impl
          return out;
        }
      };
    
      Internal<Foo, Bar> data_;
    
    public:
      void print() const
      {
        /*out is a std::ostream*/
        out << data_;
      }
    };
    
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