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Home/ Questions/Q 8702475
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:39:47+00:00 2026-06-13T02:39:47+00:00

Can’t access the control in a listview error Object reference not set to an

  • 0

Can’t access the control in a listview

error

Object reference not set to an instance of an object.

.cs

public void lnkaddtocart_Command(Object sender, CommandEventArgs e)
{
  ((TextBox)ListView_ProductDetails.FindControl("txtbox_pqty")).Visible = false;   
}

.aspx

<asp:ListView runat="server" ID="ListView_ProductDetails">
     <LayoutTemplate>
        <asp:PlaceHolder ID="itemPlaceholder" runat="server"></asp:PlaceHolder>
     </LayoutTemplate>
     <ItemTemplate>
              <div class="qty">
                  Qty:
                  <asp:TextBox ID="txtbox_pqty" Text="1" runat="server"/>
                  <input type="hidden" name="product_id" size="2" value="41" />
                       <asp:LinkButton ID="lnkaddtocart" runat="server" 
                            CommandArgument='<%#Eval("pid") %>' 
                            OnCommand="lnkaddtocart_Command"  
                            cssclass="button">
                               <span>Add to Cart</span>
                        </asp:LinkButton>
                  </div>
    </ItemTemplate>
</asp:ListView>
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  1. Editorial Team
    Editorial Team
    2026-06-13T02:39:49+00:00Added an answer on June 13, 2026 at 2:39 am

    You need to use FindControl on the NamingContainer of the TextBox which is the ListViewItem and not the ListView. Therefore you can use the LinkButton's NamingContainer property to find the ListViewItem.

    var ctrl = (Control) sender;
    var lvi = (ListViewItem) ctrl.NamingContainer;
    var txt = (TextBox)lvi.FindControl("txtbox_pqty");
    txt.Visible = false; 
    
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