Question

char ch[2];
ch[0] = 'h';
ch[1] = '\0';

or can i just do

char ch[1];
ch[0] = 'h';

in which ‘\0’ would already be implied?

The reason why i’m doing it this way is because my program has a loop in it in which i would constantly be changing this character and concatenating it to a longer string.

Answer 1

Assigning just ch[0] will not assign zero to the ch[1]. You can initialize both characters in the array with a string literal in a single line, like this:

char ch[2] = "h";

This will put 'h' into ch[0], and a terminating zero into ch[1].