Question

char *host;

host = malloc(64 * sizeof(char)); /* spazio per 64 caratteri */
memset(host,0x00,host[63]);

I have a doubt: pointer can be seen as an “array”??
With the above code am i putting NULL into the 64 byte? (to prevent buffer overflow)

Answer 1

Even if your code was correct (see @Dietrich’s answer), it doesn’t prevent buffer overflow. I can do this:

strcpy(host, "A very large string that's definitely a lot longer than 64 characters, so it will cause you a great deal of misery");