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char *pointer1;
char *pointer2;
pointer1 = new char[256];
pointer2 = pointer1;
delete [] pointer1;
In other words, do I have to do delete [] pointer2 as well?
Thanks!
Nope, that code is fine and won’t leak memory.
You only have to use delete[] once because you’ve only used one new to allocate an area for memory, even though there are two pointers to that same memory.