char s[] = "hello world";
char s[] = {'h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd', 0};
Are these two lines of code equivalent in C++?
char s[] = hello world; char s[] = {‘h’, ‘e’, ‘l’, ‘l’, ‘o’, ‘
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char s[] = "hello world";
char s[] = {'h', 'e', 'l', 'l', 'o', ' ', 'w', 'o', 'r', 'l', 'd', 0};
Are these two lines of code equivalent in C++?
No, the first one initialises the array by copying from a string literal which is stored in static memory. The second, which is initialised from an array initialiser list, probably doesn’t create anything in static memory, but generates instructions to move constant numbers (intrinsic to the instructions) into each position in the array.
Additionally, if two things are equal then applying the same transformation to them will also result in an equality. However, changing both to pointers instead of arrays (and adding const) will prevent the one with the initialiser list from compiling, so there they further differ.
Ignoring those differences, what you end up with in the array will be the same either way.