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char* XX (char* str)
{
// CONCAT an existing string with str , and return to user
}
And i call this program by:
XX ( strdup("CHCHCH") );
Will this cause a leak while not releasing what strdup() generates ?
It’s unlikely that free the result of XX() will do the job.
(Please let me know both in C and C++ , thanks !)
Unless the XX function free()’s the argument passed in, yes this will cause a memory leak in both C and C++.