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Home/ Questions/Q 832941
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:26:29+00:00 2026-05-15T04:26:29+00:00

Check client side that any 2 out of three fields have been completed before

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  1. Check client side that any 2 out of three fields have been completed before allowing submision of a form
  2. Show/hide data capture fields based on the value of a check box (all client side)?
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  1. Editorial Team
    Editorial Team
    2026-05-15T04:26:30+00:00Added an answer on May 15, 2026 at 4:26 am

    Apex 4.0 has the new feature called Dynamic Actions that can perform Javascript and AJAX processing that you define declaratively, i.e. without having to write any (or much) Javascript.

    1) Check client side that any 2 out of three fields have been completed before allowing submision of a form

    You can create a Dynamic Action that fires on page submit, performs a test, and depending on whether the test returns TRUE or FALSE cancels the submit. However, from my understanding of Dynamic Actions (which you can try out yourself at http://tryapexnow.com) in this example the condition to test would be a Javascript expression like this:

    ($v('P1_FIELD1') != '' && $v('P1_FIELD2') != '')
    || ($v('P1_FIELD1') != '' && $v('P1_FIELD3') != '')
    || ($v('P1_FIELD2') != '' && $v('P1_FIELD3') != '')
    

    (I hope I have that syntax correct.)

    2) Show/hide data capture fields based on the value of a check box (all client side)

    This can be done without writing any Javascript, using a Dynamic Action. Assuming the checkbox value is ‘Y’ when checked then the Dynamic Action’s attributes would be something like:

    Event:       Change
    Item:        P1_CHECKBOX
    Condition:   Equal To
    Value:       Y
    True Action: Hide Item(s)
      Items: P1_FIELD1, P1_FIELD2, P1_FIELD3
    False Action: Show Item(s)
      Items: P1_FIELD1, P1_FIELD2, P1_FIELD3
    
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