Question

class A
  def self.a
    puts "self: #{self}; superclass: #{superclass}"
  end
end

class B < A
  class << self; undef_method(:a); end  # I'm not allowed to use B.a
  def self.b
    # here I want to call A.a with B as self.
  end
end  

A.a  #=> self: A; superclass: Object
B.b  #=> self: B; superclass: A (expected)

I don’t want an alias_method solution. I’m looking for something like this.

UPDATE

The solution doesn’t need to be any similar to the link above; it’s only a suggestion. For example, I tried to do:

class B < A
  def self.b
    instance_eval(&A.method(:a).to_proc)
  end
end

but this way I get an weird ArgumentError on Ruby 1.8.7.

Answer 1

Only solution here is to use B.a.

class B < A
  def self.b
    a #=> self: B; superclass: A
  end
end