Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9254893
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 18, 20262026-06-18T11:35:16+00:00 2026-06-18T11:35:16+00:00

class a { } $obj1 = new a(); $obj2 = new a(); $obj3 =

  • 0
class a {

}


$obj1 = new a();
$obj2 = new a();
$obj3 = new a();

May be very trite, but… how many object creates this code?

I think, may be this code greates only 1 object in this line $obj1 = new a(); and $obj2 and $obj3 just indicate on an already created object?

I am wrong?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-18T11:35:18+00:00Added an answer on June 18, 2026 at 11:35 am

    The code will create three distinct objects, and each variable will reference a different one. new always constructs a new object instance.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have simple code: public class testing { private static Object objToSync = new
I have this object Object1 defined as public Object1(String item, List<Object2> obj2) in a
I managed to get this code to compile with out error. But somehow it
I have the following situation: In project A, an object (say Obj1 of class
Here's my binding source object: Public Class MyListObject Private _mylist As New ObservableCollection(Of String)
Class 1 private void checkDuplicateCustomer(BulkCustomerVO bulkCustomerVO) { PagedDuplicateCustomerVO duplicateCustomerVO = new PagedDuplicateCustomerVO(); duplicateCustomerVO.setCustomer(bulkCustomerVO.getCustomerVO()); duplicateCustomerVO
class A: pass def b(self): print('b') A.b = b a = A() At this
Will garbage collector free resources for cross referenced object/class, which is no longer referenced
Please have a glance at this program: class CopyCon { public: char *name; CopyCon()
I have a class containing Map whose key is string and value is object

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.