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Home/ Questions/Q 8206207
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T08:35:20+00:00 2026-06-07T08:35:20+00:00

class A{ @Override public int hashCode() { return 10; } } public class SampleClass

  • 0
class A{

      @Override
      public int hashCode() {
        return 10;
    }
}

public class SampleClass {

    public static void main(String[] args){
        Map map = new HashMap();

        map.put(new A(), "A");
        map.put(new A(), "B");

        System.out.println(map.size());

        System.out.println(new A().hashCode());
        System.out.println(new A().hashCode());
    }
}

Output :-

2

10

10

Why 2???. If we are implementing hashCode method which is returning same integer. Should not the size be 1???

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T08:35:21+00:00Added an answer on June 7, 2026 at 8:35 am

    You haven’t overriden equals(Object), so they don’t compare as equal.

    Just because two objects have the same hash code doesn’t mean HashMap assumes they’re the same — indeed, if that was the case, that would be really, really bad.

    If you want two A objects to be treated as equal by HashMap, you must override equals(Object) in A to define one A as equal to another.

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