Question

class a{
  public void foo(int a){
     System.out.println("super");
  }
}
class b extends a{
  public void foo(int a){
     System.out.println("sub");
  }
}

And this is how I wrote my code to call it

a ob = new b(); 
ob.foo(7);

but it calls the subclass method ?

Answer 1

… but it calls the subclass method

That’s the WHOLE POINT of overriding … so that when you call the method on an instance the subclass you get the subclasses override of the method!

On the other hand, the subclass itself can call the overridden version of the method in its superclass:

class A {
    public void foo() {
        System.out.println("super");
    }
}

class B extends A {
    public void foo() {
        super.foo();  // call the overridden method
        System.out.println("sub");
    }
}

… which will print

super
sub

if you call foo on a B instance.

---

are you guys really sure that there is no other method to get around this problem ?

1. Yes
2. I don’t see why you think it is a “problem”.