Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 709289
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T04:29:15+00:00 2026-05-14T04:29:15+00:00

class A { void F() { System.out.println(a); }} class B extends A { void

  • 0
class A           { void F() { System.out.println("a"); }}
class B extends A { void F() { System.out.println("b"); }}

public class X {
    public static void main(String[] args) {
        A objA = new B();
        objA.F();
    }
}

Here, F() is being invoked dynamically, isn’t it?

This article says:

… the Java bytecode doesn’t support
dynamic method invocation. There are
three supported invocations modes :
invokestatic, invokespecial,
invokeinterface or invokevirtual.
These modes allows to call methods
with known signature. We talk of
strongly typed language. This allows
to to make some checks directly at
compile time.

On the other side, the dynamic
languages use dynamic types. So we can
call a method unknown at the compile
time, but that’s completely impossible
with the Java bytecode.

What am I missing?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T04:29:15+00:00Added an answer on May 14, 2026 at 4:29 am

    You are confusing dynamic invocation with dynamic binding..

    The first one allows the type checker to accept programs in which you are not sure if a method will be present on an object at run-time, while dynamic binding just chooses the right implementation according to the runtime type of the object but maintaining the statically type checking.

    What does it mean?

    It means that in your example, Java will call the implementation on object B because the runtime type of the objA variable is B; and it will compile because it knows that a B is a A so the method invocation won’t fail at runtime (objA will have a F implementation for sure).

    With dynamic invocation instead it won’t check at compile time that the type of the object on which you are calling F contains that method, of course it will raise an exception if during execution the method won’t be available on specified object.

    Just for trivia: the invokedynamic feature will be added with Java7 because many scripting languages have been written to work on top of JVM and the lack of a dynamic invocation feature forced the developers of these languages to add a middle layer between the script and the real JVM that cares about dynamic invocation using the reflection. Of course this approach causes a lot of overhead (think about Grovvy’s MetaClass), that’s why Sun decided to give them a help..

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 371k
  • Answers 371k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer <?xml is being mistaken for PHP short-tag, try echoing it… May 14, 2026 at 7:09 pm
  • Editorial Team
    Editorial Team added an answer How about using a 3rd party tool to compare and… May 14, 2026 at 7:09 pm
  • Editorial Team
    Editorial Team added an answer And then there is the strong recommendation that an event… May 14, 2026 at 7:09 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.