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Home/ Questions/Q 8698057
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T01:39:39+00:00 2026-06-13T01:39:39+00:00

class Animal{} class Dog extends Animal{} class Cat extends Animal{} public class Mixer<A extends

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class Animal{}
class Dog extends Animal{}
class Cat extends Animal{}
public class Mixer<A extends Animal>{
    public <C extends Cat> Mixer<? super Dog> useMe(A a, C c){
        //return new Mixer<Object>();//KO
        return new Mixer<Animal>(); //OK
    }
}

The return parameter is Mixer<? super Dog> so if is a defined with a lower bounded wildcard

Why do I have a compiler error when I return a Mixer<Object> and there is no compiler error with Mixer<Animal>?

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  1. Editorial Team
    Editorial Team
    2026-06-13T01:39:40+00:00Added an answer on June 13, 2026 at 1:39 am

    The problem is not in the return type of your method, rather it is the Generic Type bound to your class Mixer.

    Let’s see what went wrong: –

    public <C extends Cat> Mixer<? super Dog> useMe(A a, C c)
    

    The return type Mixer<? super Dog> means, you can return any Mixer of type Dog or a super-type of Dog, may be Animal.

        //return new Mixer<Object>();//KO
        return new Mixer<Animal>(); //OK
    

    So, both the return statments would have worked fine, because, both Animal and Object is a super-type of Dog.

    But, the reason why the first one does not fits in is because, you have declared your class as: –

    public class Mixer<A extends Animal>
    

    So, you have bound your type that can be associated with Mixer class to either Animal or its subtype.
    Now, since, Object is not a subtype of Animal, you can’t just create: –

    new Mixer<Object>();
    

    So, you can create instances of your class like:-

    new Mixer<Animal>(); // OR
    new Mixer<Dog>();  // Dog extends Animal  // OR
    new Mixer<Cat>();  // Cat extends Animal
    
    // **** But NOT like this ******
    new Mixer<Object>();  // Object does not extend Animal
    
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