class base {
public:
base a;
};
It gives compilation error.
class base {
public:
static base a;
};
whereas this code does not give compilation error
class base { public: base a; }; It gives compilation error. class base {
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class base {
public:
base a;
};
It gives compilation error.
class base {
public:
static base a;
};
whereas this code does not give compilation error
Because
staticclass members are not stored in the class instance, that’s why astaticwould work.Storing an object inside another object of the same type would break the runtime – infinite size, right?
What would
sizeofreturn? The size of the object needs to be known by the compiler, but since it contains an object of the same type, it doesn’t make sense.