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Editorial Team
Asked: May 15, 20262026-05-15T10:03:31+00:00 2026-05-15T10:03:31+00:00

class Base { public: Base() {} void Foo(int x) {…} }; class Derived :

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class Base {
    public:
    Base() {}

    void Foo(int x) {...}
};

class Derived : public Base {
    public:
    Derived(int args) {
        /* process args in some way */

        Foo(result);
    }
};

Is it allowed to call a method of the base class in the constructor of the derived class?
I would imagine this is fine as the Base object should be fully constructed, but I wanted to check just in case.

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:03:31+00:00Added an answer on May 15, 2026 at 10:03 am

    Is it allowed to call a method of the base class in the constructor of the derived class?

    Yes. Just watch out for virtual functions. If an class derived from Derived overrides a virtual function, while constructing Derived as a sub-object of that further derived class, the dynamic type always is Derived, so no virtual functions overridden in further derived classes are called. (The same goes for the destructor, BTW.)

    I would imagine this is fine as the Base object should be fully constructed, but I wanted to check just in case.

    Your reasoning is right.

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