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Home/ Questions/Q 8450063
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T10:52:16+00:00 2026-06-10T10:52:16+00:00

class Base { public: int a; Base():a(0) {} virtual ~Base(); } class Derived :

  • 0
class Base {
public:
    int a;
    Base():a(0) {}
    virtual ~Base();
}
class Derived : public Base {
public:
    int b;
    Derived():b(0) {
        Base* pBase = static_cast<Base*>(this);
        pBase->Base();
    }
    ~Derived();
}

Is the call to the base class constructor necessary or does c++ do this automatically? e.g.
Does C++ require you to initialize base class members from any derived class?

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  1. Editorial Team
    Editorial Team
    2026-06-10T10:52:17+00:00Added an answer on June 10, 2026 at 10:52 am

    The base class’s constructor will automatically be called before the derived class’s constructor is called.

    You can explicitly specify which base constructor to call (if it has multiple) using initialization lists:

    class Base {
      public:
        int a;
        Base():a(0) {}
        Base(int a):a(a) {}
    };
    class Derived {
      public:
        int b;
        Derived():Base(),b(0) {}
        Derived(int a):Base(a),b(0) {}
    };
    
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